Here is a solution(?) based on regexp
>> cac = cssm;
>> cac{:}
ans =
MOD11C1.A2013001.005.2013015221704.hdf
ans =
MOD11C1.A2013001.005.2013015221704.hdf
>>
where
function cac = cssm()
str = fileread( 'cssm.txt' );
name_xpr = '[\w\.]+\.hdf';
cac = regexp( str, name_xpr, 'match' );
end
and cssm.txt contains the text of your question. Two identical name seems to be correct. You might want to apply unique
 
In response to comments:
My mistake illustrates a problem with regular expressions. Expressions often matches unexpected strings. I missed the case that ".hdf" is part of the base name rather than an extension. Now I have added that ".hdf" should be followed by "\s, Any white-space character; equivalent to [\f\n\r\t\v]". However, that white-space is not included in the output.
>> cssm
ans =
'MOD11C1.A2013001.005.2013015221704.hdf'
function cac = cssm()
str = fileread( 'cssm.txt' );
name_xpr = '[\w\.]+\.hdf(?=\s)';
cac = regexp( str, name_xpr, 'match' );
end
 
Stephen Cobeldick already proposed this modification to the expression. I like Stephen's list, which helps to pinpoint the unique characteristics of the string. It triggers thinking. Does the filename always start with "MOD"? Could "MOD" appear in the middle of the name? It's risky to deduce rules out of small samples. If the name shall always start with "MOD"
name_xpr = '(?<=\s)MOD[\w\.]+\.hdf(?=\s)';
is a better expression.
