Change non-numerics into NaN & split cell array by delimiter
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I have a 3000x1 cell array of depth in centimeters with both letters and numbers
EX:
A = {organic layer, 5~10, 15~20, 30~50, not specified}
I want to change all of the non-numeric bins into NaN and then split this array into both the lower and upper bound of depth so that
Lower Bound = {NaN, 5, 15, 30, NaN}; Upper Bound = {NaN, 10, 20, 50, NaN};
I tried to use numind = cellfun(@isnumeric, A) to find the numeric indices and then from that find all of the indices that ARENT numeric, to replace with NaN, but it simply says that all of the bins are not numeric because of the '~' between the integers.
Is there any way that I could accomplish this?
Thanks, Melissa
6 个评论
Guillaume
2014-12-4
There are some cells in your cell array that contain numbers instead of strings. To see which ones:
find(cellfun(@(x) isnumeric(x), Depthcm))
采纳的回答
Guillaume
2014-12-4
Once you've fixed the numeric values in you cell array, with for example:
Depthcm(cellfun(@(x) isnumeric(x), Depthcm)) = {''};
You can get your arrays with:
splitdepth = regexp(Depthcm, '~', 'split');
splitdepth(cellfun(@(c) numel(c) == 1, splitdepth)) = {{'Nan' 'NaN'}};
bounds = str2double(vertcat(splitdepth{:}));
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Star Strider
2014-12-4
I’m not certain how your cell is organised, but assuming the structure here, this code will at least get you the numbers:
A = {'organic layer', '5~10', '15~20', '30~50', 'not specified'};
B = strrep(A, '~', ' ');
C = str2num(char((B(2:4)')));
producing:
C =
5 10
15 20
30 50
I worked with other options but couldn’t get them to produce this any more efficiently.
3 个评论
Star Strider
2014-12-4
When I use exactly that code and ‘A’, it works without error (or I’d not have posted it).
What’s different about my ‘A’ and your cell array?
(I’m using R2014b, so there could be version differences.)
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