Extract float from a filename

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K3iTH
K3iTH 2022-2-24
评论: K3iTH 2022-2-24
Hi all,
I have a list of files in a directory with a name of "time_ xx" where xx is number (for e.g 0.20, 0.41, 0.61, 0.82,...) the number is not does not have a fixed expression. I want like to extract these number and used it for calculation later.
May I know what function can I used to extract the number from a filename without extension?
Thank you.

采纳的回答

DGM
DGM 2022-2-24
编辑:DGM 2022-2-24
Well I guess this is one way. There are probably more elegant ways of unpacking the nested cell array and converting to numeric, but this is how I did it.
names = {'time_0.709'
'time_5.61'
'time_0.2081'
'time_45.027'
'time_90'};
filenums = str2double(regexprep(names,'.*_(?=(\d*\.*)+$)',''))
filenums = 5×1
0.7090 5.6100 0.2081 45.0270 90.0000
This looks for any number between an underscore and the end of each name. The filename prefix is ignored except for the underscore.
I guess if you wanted rely on the prefix, you could alternatively just do:
names = {'time_0.709'
'time_5.61'
'time_0.2081'
'time_45.027'
'time_90'};
filenums = str2double(strrep(names,'time_',''))
filenums = 5×1
0.7090 5.6100 0.2081 45.0270 90.0000
  1 个评论
K3iTH
K3iTH 2022-2-24
Hi DGM,
Thank you for you help. Both method is very useful. Persoanlly, I seldom use "regexprep" but the second method "strrep" is fast and direct.
Once again, thank you so much!

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