How do you use logical operators for this problem in multiple unnested if statements?

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Caroline F
Caroline F 2022-2-26
评论： Steven Lord 2022-2-27
Ran in:
I'm given the following:
x=0:3:21;
y=10;
z=15;
When x < y and z, the code has to dispaly "Value is less that y and z". When y<x<z, the code has to display "Value is between y and z". When x > y and z, the code has to display " Value is greater than y and z." I was able to do this with a for loop and nested if statements, but I also have to write the code using unnested if statements. My code either gives logical array instead of a displayed answer or an error statement. This is what I have so far, and it gives a logical array.
x=0:3:21;
y=10;
z=15;
if x<y %& x<z %y is less than z, so if x is less than y, then x must also be less than z
disp('Value is less than y and z')
elseif x>z & x>y %z is greater than y, so if x is greater than z, then x must also be greater than y
disp('Value is more than y and z')
else y<x<z
disp('Value is between y and z')
end
ans = 1×8 logical array
1 1 1 1 1 1 1 1
Value is between y and z

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回答（1 个）

Image Analyst
Image Analyst 2022-2-26
Replace
else y<x<z
with
elseif (y < x) && (x < z)
  1 个评论
Steven Lord
Steven Lord 2022-2-27
Ran in:
Because x is a vector that won't work. You could wrap the conditions in all or any to get it to work or you could use the non-short-circuiting and operator &.
x = 1:10;
y = 0;
z = 11;
all(y < x) && all(x < z) % true
ans = logical
1
(y < x) & (x < z) % vector of true values
ans = 1×10 logical array
1 1 1 1 1 1 1 1 1 1
(y < x) && (x < z) % error
Operands to the logical and (&&) and or (||) operators must be convertible to logical scalar values.

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