Make first and last element of array 0

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Sarah Gomez
Sarah Gomez 2022-2-28
评论： Stephen23 2022-3-21
N = 12*0.5;
TAU_max = 15;
for i = 1:N
TAU(i,:) = i*(TAU_max/N);
end
I have a little loop here that creates a column vector with my dummy variables. But how I do make it so the (1,1) and (1:N) elements are 0 while still preserving my original values?
  1 个评论
Stephen23
Stephen23 2022-3-21
Ran in:
You don't need a loop:
N = 12*0.5;
TAU_max = 15;
TAU = (1:N)*(TAU_max/N)
TAU = 1×6
2.5000 5.0000 7.5000 10.0000 12.5000 15.0000

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回答（2 个）

Voss
Voss 2022-2-28
编辑：Voss 2022-2-28
Ran in:
Pre-allocate TAU as a vector of zeros, then just set elements 2 through N-1:
N = 12*0.5;
TAU_max = 15;
TAU = zeros(N,1); % pre-allocate
for i = 2:N-1
TAU(i,:) = i*TAU_max/N;
end
disp(TAU);
0 5.0000 7.5000 10.0000 12.5000 0
Alternatively, set all elements and afterward set elements 1 and N to zero:
N = 12*0.5;
TAU_max = 15;
TAU = zeros(N,1);
for i = 1:N
TAU(i,:) = i*TAU_max/N;
end
TAU([1 N],:) = 0;
disp(TAU);
0 5.0000 7.5000 10.0000 12.5000 0
Arif Hoq
Arif Hoq 2022-2-28
编辑：Arif Hoq 2022-2-28
Ran in:
try this:
N = 12*0.5;
TAU_max = 15;
for i = 1:N
TAU(i,:) = i*(TAU_max/N);
TAU([1 N],:)=0;
end
disp(TAU)
0 5.0000 7.5000 10.0000 12.5000 0

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