Does it have a statement for replacing repeated multiple if and elseif statements?

3 次查看(过去 30 天)
I have a code:
a = 0:0.001:1;
b = 0.03*sin(a);
for i = 1:length(a),
d = 0;
if b(i) <= 0.02;
if 0 < b(i) <= 0.1*pi/180
c = 0:0.1*pi/180:10*pi/180;
elseif 0.1*pi/180 < b(i) <= 0.2*pi/180
c = 0.1*pi/180:0.1*pi/180:10*pi/180;
elseif 0.2*pi/180 < b(i) <= 0.3*pi/180
c = 0.2*pi/180:0.1*pi/180:10*pi/180;
elseif 0.3*pi/180 < b(i) <= 0.4*pi/180
c = 0.3*pi/180:0.1*pi/180:10*pi/180;
elseif 0.4*pi/180 < b(i) <= 0.5*pi/180
c = 0.4*pi/180:0.1*pi/180:10*pi/180;
elseif 0.5*pi/180 < b(i) <= 0.6*pi/180
c = 0.5*pi/180:0.1*pi/180:10*pi/180;
elseif 0.6*pi/180 < b(i) <= 0.7*pi/180
c = 0.6*pi/180:0.1*pi/180:10*pi/180;
elseif 0.7*pi/180 < b(i) <= 0.8*pi/180
c = 0.7*pi/180:0.1*pi/180:10*pi/180;
elseif 0.8*pi/180 < b(i) <= 0.9*pi/180
c = 0.8*pi/180:0.1*pi/180:10*pi/180;
elseif 0.9*pi/180 < b(i) <= 1*pi/180
c = 0.9*pi/180:0.1*pi/180:10*pi/180;
end
end
for k = 1:length(c),
d = d + b(1,i)*c(1,k);
end
e(1,i) = d;
end
I wonder if there is any way to get the same result by replacing the repeated elseif statement.
Thank you!
  3 个评论
Cris LaPierre
Cris LaPierre 2022-2-28
Note that your conditional statements are not robust. Consider the following.
0 < 5 < 6
ans = logical
1
0 < -5 < 6
ans = logical
1
Both statements evaluate as true, though you likely intend for the 2nd one to be false. I would be more explicit with how I write these.
0 < -5 && -5 < 6
ans = logical
0

请先登录,再进行评论。

采纳的回答

David Hill
David Hill 2022-2-28
a = 0:0.001:1;
b = 0.03*sin(a);
interval=0:.1*pi/180:pi/180;
[~,~,idx]=histcounts(b,interval);
b=b(idx~=0);
for k=1:length(b)
e(k)=sum(b(k)*((idx(k)-1)*.1*pi/180:.1*pi/180:10*pi/180));
end

更多回答(1 个)

Walter Roberson
Walter Roberson 2022-2-28
Use discretize() to determine the range of c values that you want to use.
Or... just take
round((b*180/pi),1)*pi/180
as the starting point for c.

类别

Help CenterFile Exchange 中查找有关 MATLAB Coder 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by