How to perform integration of product of multiple function inside a for loop?

1 次查看(过去 30 天)
Hello everyone, I am having some troube integrating insiide a for loop. I am providing the code below. The code works wiithout the integration part when is not inside a loop. I am having Undefined operator '*' for input arguments of type 'function_handle' error. Can anyone fix my problem. It will be a great help and learning opportunity.
clc
clear all
close all
Fs= 2.16*10^-5*pi; % Geometrical Factor for sun
h= 4.136*10^-15; % Plancks Constant
c= 3*10^8; % Speed of light
k = 8.6173*10^-5; % Boltzmanns Constant
Ts=5760; % Temparature of the sun
q=1.6*10^-19; % electronic charge
T=300; % ambient temparature
beta=7.021*10^-4;
gamma=1108;
Eg0_1=1.1557;
Eg0_2=2.5;
Egd0=3.2;
Eg1=Eg0_1-((beta*(T^2))/(T+gamma));
Eg2=Eg0_2-((beta*(T^2))/(T+gamma));
Egd=Egd0-((beta*(T^2))/(T+gamma));
Ep1=1.827*10^-2;
Ep2=5.773*10^-2;
C1=5.5;
C2=4.0;
A1=3.231*10^2;
A2=7.237*10^3;
Ad=1.052*10^6;
A=((2*Fs)/((h^3)*(c^2)));
lambda_min=200*10^-9;
lambda_max= 1200*10^-9;
depth=0.1:0.01:5;
num=numel(depth);
G_t=nan(1,num);
for a=1:num
x=depth(a);
Photon_flux=@(lambda)((A*((((h*c)/lambda)^2)/(exp((((h*c)/lambda)/(k*Ts)))-1)))*q);
Alpha= @(lambda)((((C1*A1)*(((((h*c)/lambda)-Eg1+Ep1)^2)/(exp(Ep1/(k*T))-1)))+((C1*A1)*(((((h*c)/lambda)-Eg1-Ep1)^2)/(1-exp(-Ep1/(k*T)))))+(Ad*((((h*c)/lambda)-Egd)^(1/2))))*(10^-4));
Generation_Rate=@(lambda)(Photon_flux*Alpha*exp(-Alpha*x));
G_t(a)=integral(Generation_Rate,lambda_min,lambda_max);
end
plot(depth,G_t)
xlabel('depth \microm'),ylabel('Total Generation Rate')

采纳的回答

Torsten
Torsten 2022-3-1
for a=1:num
x=depth(a);
Photon_flux=@(lambda)((A*((((h*c)/lambda)^2)/(exp((((h*c)/lambda)/(k*Ts)))-1)))*q);
Alpha= @(lambda)((((C1*A1)*(((((h*c)/lambda)-Eg1+Ep1)^2)/(exp(Ep1/(k*T))-1)))+((C1*A1)*(((((h*c)/lambda)-Eg1-Ep1)^2)/(1-exp(-Ep1/(k*T)))))+(Ad*((((h*c)/lambda)-Egd)^(1/2))))*(10^-4));
Generation_Rate=@(lambda)(Photon_flux(lambda)*Alpha(lambda)*exp(-Alpha(lambda)*x));
G_t(a)=integral(Generation_Rate,lambda_min,lambda_max,'ArrayValued',true);
end

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 General Applications 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by