Index exceeds matrix dimensions error

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hi i was running this simple code,but i got this error,any idea how to fix it?
L = 140; % Length of signal
NFFT = 2^nextpow2(L); % Next power of 2 from length of y
YY = fft(rawdata,NFFT)/L;
((((((((((Index exceeds matrix dimensions.))))))))
Error in Untitled2 (line 11)
YY = fft(rawdata,NFFT)/L;
  4 个评论
Star Strider
Star Strider 2014-12-10
Next step:
In the Command Window, type
which fft -all
after the error.
I get 6 answers, all in: C:\Program Files\MATLAB\.
mohamad mohamad
mohamad mohamad 2014-12-10
编辑:Star Strider 2014-12-10
fft is a variable.
built-in (C:\MATLAB\R2012a\toolbox\matlab\datafun\@logical\fft) % Shadowed logical method
built-in (C:\MATLAB\R2012a\toolbox\matlab\datafun\@single\fft) % Shadowed single method
built-in (C:\MATLAB\R2012a\toolbox\matlab\datafun\@double\fft) % Shadowed double method
C:\MATLAB\R2012a\toolbox\matlab\datafun\@uint8\fft.m % Shadowed uint8 method
C:\MATLAB\R2012a\toolbox\matlab\datafun\@uint16\fft.m % Shadowed uint16 method
C:\MATLAB\R2012a\toolbox\comm\comm\@gf\fft.m % Shadowed gf method
C:\MATLAB\R2012a\toolbox\distcomp\parallel\@codistributed\fft.m % Shadowed codistributed method
C:\MATLAB\R2012a\toolbox\dsp\filterdesign\@qfft\fft.m % Shadowed qfft method
C:\MATLAB\R2012a\toolbox\ident\ident\@iddata\fft.m % Shadowed iddata method

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采纳的回答

Image Analyst
Image Analyst 2014-12-10
How can you take 256 samples from an array with 140 samples? Maybe you need to pad it with zeros or something
newArray = [oldArray, zeros(1, NFFT - length(oldArray))];
  6 个评论
mohamad mohamad
mohamad mohamad 2014-12-10
my vector was a column vector and could not be concatenated with row vector zeros(1, NFFT - length(rawdata)).so i changed it to zeros(NFFT - (length(rawdata)), 1)]; and it works properly thanks indeed for your fast replays
Image Analyst
Image Analyst 2014-12-10
OK, glad it works, though I don't know why since the help for fft() said that it would do that padding for you.

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