How to make a function that outputs true or false (logical) if a number inputted is in a predetermined vector?

80 次查看（过去 30 天）
Jacob Boulrice
Jacob Boulrice 2022-3-1
评论： Walter Roberson 2022-3-2
% Here is my code:
function [x] = testLucky1
% testLucky(x) - determine whether x is a lucky number
% return true (1) if x is a lucky number
% return false (0) if x is not a lucky number
secretLucky = [19,22,5,9,11,15,21];
x = input('Enter a number: ');
for k = 1:length(secretLucky)
if secretLucky(k) == x
true
else
false
end
end
% The issue I'm having is that when I enter a single number like
% 19/22/5/9/11/15/21, the command window shows a logical statement of 1
% alongside logical statements of 0.
% For example, if I input 19, the first logical statement in the command
% window will be 1, and the remaining 6 logical statements will be 0.
% My question is, how can I make the output in the command window be a
% SINGLE logical statement of 1 if ANY of the numbers in vector secretLucky
% is entered? And if a number that is not ANY of the numbers in vector
% secretLucky is entered, how can I have a SINGLE logical statement of 0?
% Does my issue stem from the fact the ouput of true/false is based on my
% variable k? If so what should I do to change this?

请先登录，再回答此问题。

采纳的回答

Walter Roberson
Walter Roberson 2022-3-1
found = false;
for k = 1:10
if x(k) == 7
found = true;
end
end
found
  2 个评论
Jacob Boulrice
Jacob Boulrice 2022-3-1
Hey, thank you for the response.
Any chance you could explain what this means? And where I should add this in my code?
One question I have is why you set k to 1:10?
Walter Roberson
Walter Roberson 2022-3-2
The intent is to illustrate initializing a state variable, changing it conditionally, and then examining the state afterwards.
Key point: do not display true when you find a match, set the state variable instead. And do not display the false when a match fails, just go on to the next test. You do not care in this context whether the input did not match 7 out of the 8 possibilities: you only care that it matched one of the possibilities.

请先登录，再进行评论。

更多回答（1 个）

Davide Masiello
Davide Masiello 2022-3-1
编辑：Davide Masiello 2022-3-1
function testLucky
% testLucky - determine whether x is a lucky number
% return true (1) if x is a lucky number
% return false (0) if x is not a lucky number
secretLucky = [19,22,5,9,11,15,21];
x = input('Enter a number: ');
result = false;
for i = 1:numel(secretLucky)
if x == secretLucky(i)
result = true;
end
end
result
end

类别

在 Help Center 和 File Exchange 中查找有关 Loops and Conditional Statements 的更多信息

标签

产品


版本

R2021b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by