How do you divide 120 by x when x is (3,6] starting with x=0

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Caroline F
Caroline F 2022-3-5
回答： Walter Roberson 2022-3-5
Ran in:
I am trying to do a while statement that divdes 120 by the numbers between (3,6] and only gives nonzero() answers, but so far my code only gives me the last value "20". Is there a way to fix the code so I get all three values, 30, 24, and 20?
x=0;
while (x>2) & (x<=5)
x=x+1;
Q2(x) = 120/x;
end
disp('Q2 =')
Q2 =
disp(nonzeros(Q2))
Unrecognized function or variable 'Q2'.

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采纳的回答

Walter Roberson
Walter Roberson 2022-3-5
x=0;
while (x>2) & (x<=5)
Your x starts out at 0 which immediately fails the x>2 test.
Consider
x=0;
while x<=6
if (x>3) & (x<=6)
Now imagine that you were keeping a counter of how many values you have found, and you used the counter to index the output variable...

更多回答（1 个）

David Hill
David Hill 2022-3-5
编辑：David Hill 2022-3-5
Q2=120./(4:6)

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