Generate coordinates for plotting a hexagonal mesh with the nsidedpoly function

Question

Yro 2022-3-6

1
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1664474-generate-coordinates-for-plotting-a-hexagonal-mesh-with-the-nsidedpoly-function

评论： Yro 2022-3-6

Hi, I am trying to plot a hexagonal mesh using the nsidedpoly function as shown in the following code. I am taking the coordinates (coord array) from a file but I want to generate them myself in the code. How can I do this, by rings and counterclockwise, as shown in the figure?

Thank in advance.

radius = 5.6617/(sqrt(3)/2);
coord = [x(230:235, :)
		x(256:262, :)
		x(282:289, :)
		x([308:310,312:316], :)
		x(334:343, :)
		x([360:364,366,368:370], :)
		x(387:396, :)
		x([414:416,418:422], :)
		x(441:448, :)
		x(468:474, :)
		x(495:500, :)];
for i = 1:length(coord)
	poly(i) = nsidedpoly(6, 'Center', coord(i, :), 'Radius', radius);
end
pg = plot(poly);
axis off
axis equal
% Convert num2str
POS = num2str(POSITIONS);
% Convert str2double
for i = 1:length(POSITIONS)	
	c = POS(i, :);
	p(i, :) = str2double(c(~isspace(c)));
end
a = 0.5;
b = 1.5;
r = (b-a).*rand(87, 1) + a;
r = [p [1:87]'];
power = repmat([], 87, 1);
power(1:6, :) = r(ib(1:6), :);
power(7:13, :) = r(ib(7:13), :);
power(14:21, :) = r(ib(14:21), :);
power(22:29, :) = r(ib(22:29), :);
power(30:39, :) = r(ib(30:39), :);
power(40:48, :) = r(ib(40:48), :);
power(49:58, :) = r(ib(49:58), :);
power(59:66, :) = r(ib(59:66), :);
power(67:74, :) = r(ib(67:74), :);
power(75:81, :) = r(ib(75:81), :);
power(82:87, :) = r(ib(82:87), :);
nLevel = 256;                                               
cmap = colormap(jet(nLevel));                               
polyFaceColor = cmap(ceil((power(:, 2)-a)*nLevel/100), :);
for i = 1:length(pg)
	pg(i).FaceColor = polyFaceColor(i, :);
	pg(i).FaceAlpha = 0.5;
end
str = num2str(power(:, 2), 4);
t2 = text(coord(:, 1), coord(:, 2), str,'HorizontalAlignment', 'center','VerticalAlignment','middle', 'FontSize', 10, 'FontName', 'Times');