Extract Value from ODE45

5 次查看(过去 30 天)
BINAY NAYAK
BINAY NAYAK 2022-3-16
I am Using below code to plot 2 graphs using ODE45. However I want to know a particular value of "t" at y(2) = 0.1
Is it possible?
%For plots
[t,y] = ode45(@odefun3,[0:0.1:50],[300; 2]);
plot(t,y(:,1))
plot(t,y(:,2))
function dydt = odefun3(t,y)
dydt = zeros(2,1);
dydt(1) = 125*0.01725*exp(-2660*(1/y(1)-1/300))*y(2)^2;
dydt(2) = -0.01725*exp(-2660*(1/y(1)-1/300))*y(2)^2;
end

回答(1 个)

Walter Roberson
Walter Roberson 2022-3-16
No, you can only interpolate the position, as there is no t value at which y(:,2) is exactly 0.1.
%For plots
[t,y] = ode45(@odefun3,[0:0.1:50],[300; 2]);
plot(t,y(:,1))
plot(t,y(:,2))
format long g
t01 = interp1(y(:,2), t, 0.1, 'spline')
t01 =
19.8851354380905
function dydt = odefun3(t,y)
dydt = zeros(2,1);
dydt(1) = 125*0.01725*exp(-2660*(1/y(1)-1/300))*y(2)^2;
dydt(2) = -0.01725*exp(-2660*(1/y(1)-1/300))*y(2)^2;
end

类别

Help CenterFile Exchange 中查找有关 Ordinary Differential Equations 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by