How to adjust dimension in xx

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jazba hafeez
jazba hafeez 2022-3-22
回答： KSSV 2022-3-22
function f = watch2(b,x,M,n,lb,ub,costfun)
xx=zeros(M,n);
for i=1:M
for j=1:n
xx(i,:)= (x(i,j) - b)+ ((x(i,j) + b)-(x(i,j)-b)).*rand;
end
end
xx;
if ob(xx)<ob(x)
x(i,:)=xx(i,:);
end %fw=xx
f=lb+(ub-lb).*x;
end

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回答（1 个）

KSSV
KSSV 2022-3-22
for i=1:M
for j=1:n
xx(i,j)= (x(i,j) - b)+ ((x(i,j) + b)-(x(i,j)-b)).*rand;
end
end

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