One problem is that ‘C’ is being used to designate the capacitor, and also the ‘ABCD’ (2,1) element. Designating the capacitor as ‘Cc’ removes that ambiguity —
syms w Cc R h11 h12 h21 h22
%matrix i would like to solve ABCD=[1 (1/(j*w*Cc))+R; 0 1]
%formular to converting ABCD to h para
A=((h11*h22)-(h12*h21))/h21
B=-h11/h21
C=-h22/h21
D=-1/h21
ABCD=[A B;C D]
ABCD = simplify(ABCD, 500)
S = ABCD == [1 (1/(1j*w*Cc))+R; 0 1]
[h11 h12 h21 h22] = solve(S,[h11 h12 h21 h22])
I also removed ‘j’ and replaced it with the imaginary operator ‘1j’ (that now appears as i) for clarity.
.
