solving PDE with boundary conditions involving derivative

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YeEn Kim
YeEn Kim 2022-3-25
评论： YeEn Kim 2022-3-26
Hi!
I'm trying to solve a PDE problem with boundary conditions: C(0,t)=Cf & dC(L,t)dz=0
My final goal is to find the C(z,t) and L.
Here is my full code for now:
Da=findDa(d_p,u,epsilon,Rho,eta);%function
constant=findConstant(epsilon, q_max, k_eq);
% z=findz(u, Da,Cf);
z = linspace(0,0.1,50);
t = linspace(0,1,50);
m = 0;
eqn = @(z,t,C,dCdz) setPDE(z,t,C,dCdz,Da,constant,u);
sol = pdepe(m,eqn,@findIC,@setBC,z,t);
C = sol(:,:,1);
function constantVal=findConstant(epsilon, q_max, k_eq)
constantVal=(1+(1-epsilon)/epsilon*q_max*k_eq);
end
function Daval=findDa(d_p,u,epsilon,Rho,eta)
Re=u*d_p*Rho/eta;
Daval=d_p*u*epsilon/(0.339+0.033*Re^0.48);
end
function [g,f,s]=setPDE(z,t,C,dCdz,Da,constant,u)
g=1;
f=Da/constant*dCdz;
s=-u/constant*dCdz;
end
function C0=findIC(z)
C0=0;
end
function [pl,ql,pr,qr]=setBC(zl,Cl,zr,Cr,t)
...
end

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采纳的回答

Torsten
Torsten 2022-3-26
Cf = ...;
bcfcn = @(zl,Cl,zr,Cr,t)setBC(zl,Cl,zr,Cr,t,Cf);
sol = pdepe(m,eqn,@findIC,bcfcn,z,t);
function [pl,ql,pr,qr]=setBC(zl,Cl,zr,Cr,t,Cf)
pl = Cl - Cf;
ql = 0.0;
pr = 0.0;
qr = 1.0;
end
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YeEn Kim
YeEn Kim 2022-3-26
I cleared it and it worked!!! Thank you so much!
Though, it still doesn't give me anything in the figure, but I guess I will slowly figure that out...
Thank you for your help XD

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