I wanna define function which has flexible number of argument.

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Dong-Gyu Jang 2014-12-26

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评论： Dong-Gyu Jang 2014-12-30

采纳的回答： Shoaibur Rahman

Hello and happy new year!

Now I'm considering to define function which has flexible arguments.

For example, let's have function F which full argument number is 3 such as F(a,b,c)

If b is 0, user don't need to assign c thus F(a,b) is enough. Otherwise full argument assignment is required.

Can I make this kind of flexible function?

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Shoaibur Rahman 2014-12-26

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编辑：Shoaibur Rahman 2014-12-26

在 MATLAB Online 中打开

function out = F(varargin)
 % do stuffs
 % y = varargin{1}+varargin{2}
 % out = y+1; etc.

For flexible number of outputs:

function varargout = F(varargin)
% do stuffs
% varargout{1} = varargin{1}-varargin{2}
% etc.

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Shoaibur Rahman 2014-12-29

This should work in this way. Anyway, it would be better to see the part of your code and the errors generated by the code.

Dong-Gyu Jang 2014-12-30

Oh, you're right. I've just not known varargin and used arbitary variable name. As the result, it was not operated! Thanks to your advice! my function is now upgraded:)

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