Matrix calculation(replacing a new value instead of matrix element)

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shirin mhd
shirin mhd 2022-3-31
评论： Voss 2022-3-31
Hi everyone
I've written this code. my purpose is to make a matrix(1*3), which each element (T1,T2,T3) of that is calculated in upper lines. But it doesn't work. what should i do?
a1=7;
a2=12;
a3=4;
w1=min([a1,a2,a3]);
f1=double(a1-w1);
f2=double(a2-w1);
f3=double(a3-w1);
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
if f1==0
final=w1;
T1=-10e10;
else
T1=f1;
end
%%%%%%%%%%%%%%%%%%%%%%%%%%%%
if f2==0
final=w1;
T2=-10e10;
else
T2=f2;
end
%%%%%%%%%%%%%%%%%%%%%%%%%%%%
if f3==0
final=w1;
T3=-10e10;
else
T3=f3;
end
T=[T1,T2,T3]
i expect after run T becomes [3 8 -10e10]
but what code does is:
T =
1.0e+11 *
0.0000 0.0000 -1.0000
in other word, I want replace some elements in a matrix with new calculated value during some steps.which part is wrong?
I appreciate any help.

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采纳的回答

the cyclist
the cyclist 2022-3-31
Ran in:
The code is doing what you expect, but the format of the output obscures the result. Try using format long, and you'll see the result more clearly:
a1=7;
a2=12;
a3=4;
w1=min([a1,a2,a3]);
f1=double(a1-w1);
f2=double(a2-w1);
f3=double(a3-w1);
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
if f1==0
final=w1;
T1=-10e10;
else
T1=f1;
end
%%%%%%%%%%%%%%%%%%%%%%%%%%%%
if f2==0
final=w1;
T2=-10e10;
else
T2=f2;
end
%%%%%%%%%%%%%%%%%%%%%%%%%%%%
if f3==0
final=w1;
T3=-10e10;
else
T3=f3;
end
format long
T=[T1,T2,T3]
T = 1×3
1.0e+11 * 0.000000000030000 0.000000000080000 -1.000000000000000
T1
T1 =
3
T2
T2 =
8
T3
T3 =
-1.000000000000000e+11

更多回答（2 个）

Voss
Voss 2022-3-31
Ran in:
The result T you get is correct. The confusion is because of how T is displayed in the Command Window. You can look at one element at a time to see them, or you can change how numbers are displayed in the Command Window:
Looking at individual elements of T:
T = [3 8 -10e10] % shows all of T, as-is
T = 1×3
1.0e+11 * 0.0000 0.0000 -1.0000
T(1)
ans = 3
T(2)
ans = 8
T(3)
ans = -1.0000e+11
Changing the Command WIndow format:
format long
T
T = 1×3
1.0e+11 * 0.000000000030000 0.000000000080000 -1.000000000000000
Image Analyst
Image Analyst 2022-3-31
Those are the values. It's just that when using 1e11 as the base, the 3 and 8 don't show in the display. To solve that put this at the top of your code
format long g

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