how do i fix inline function error?

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i m trying to make matrix (4x16)
in forloop, three modifies of 'a' are series (1 to infinite)
it works untill i added 4th a series (which means inline function. i think this line makes error)
i should add inline function and show series's sum to 160 on 4th row in matrix A
and I got this error
>> work5(0.5)
error: sum: wrong type argument 'class'
function A=work5(x)
m=1;
for k=10:10:160
n=1:k;
a= sum(nthroot(n.^2,5)./((3.^n).*(n+1)));
A(1,m)=a;
a= sum((3*n.^2+n)/(2*n.^4+nthroot(n,2)));
A(2,m)=a;
a= sum((nthroot(37,2)*n.^3)/((2*n.^3)+(3*n.^2)));
A(3,m)=a;
a= sum(inline('log(n)./(n.^2)','n'));
A(4,m)=a;
m=m+1;
end

采纳的回答

Riccardo Scorretti
Hi,
you can try this:
work5(0.5)
ans = 4×16
0.2361 0.2361 0.2361 0.2361 0.2361 0.2361 0.2361 0.2361 0.2361 0.2361 0.2361 0.2361 0.2361 0.2361 0.2361 0.2361 0.0183 0.0047 0.0021 0.0012 0.0008 0.0005 0.0004 0.0003 0.0002 0.0002 0.0002 0.0001 0.0001 0.0001 0.0001 0.0001 2.6037 2.8014 2.8760 2.9152 2.9394 2.9558 2.9677 2.9766 2.9837 2.9893 2.9939 2.9978 3.0011 3.0040 3.0064 3.0086 0.6185 0.7415 0.7927 0.8215 0.8401 0.8532 0.8630 0.8706 0.8767 0.8817 0.8859 0.8895 0.8926 0.8952 0.8976 0.8997
function A=work5(x)
m=1;
fun = @(n) log(n)./(n.^2); % ***
for k=10:10:160
n=1:k;
a= sum(nthroot(n.^2,5)./((3.^n).*(n+1)));
A(1,m)=a;
a= sum((3*n.^2+n)/(2*n.^4+nthroot(n,2)));
A(2,m)=a;
a= sum((nthroot(37,2)*n.^3)/((2*n.^3)+(3*n.^2)));
A(3,m)=a;
% a= sum(inline('log(n)./(n.^2)','n')); % ***
a = sum(fun(n));
A(4,m)=a;
m=m+1;
end
end
The problem seems to be related with the deprecated function inline.

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