Cycle of operations on vector sections

1 次查看（过去 30 天）
Lev Mihailov
Lev Mihailov 2022-4-4
评论： Lev Mihailov 2022-4-4
I'm trying to make a cycle that would process a section of the vector and return this section to me changed
x=rand(1,2302)
y=rand(1,2302)
step=100;
for i=1:size(x,2)
i1=y(i:i+step);
i2=x(i:i+step);
a(i)=myfun(i1,i2);
end
%% for example my function
function [m,s] = myfun(x,y)
n = length(x);
m = x-0.26;
s= y-0.77
end
thank you in advance

请先登录，再回答此问题。

采纳的回答

Davide Masiello
Davide Masiello 2022-4-4
The problem is myfun spits out two vectors of size 1 x step+1.
You could assign this vectors to the rows of a new matrix (see a and b in the example below) .
x = rand(1,2302);
y = rand(1,2302);
step = 100;
for i = 1:size(x,2)-step
i1 = y(i:i+step);
i2 = x(i:i+step);
[a(i,:),b(i,:)] = myfun(i1,i2);
end
function [m,s] = myfun(x,y)
n = length(x); % <--- not needed
m = x-0.26;
s= y-0.77;
end
  3 个评论
显示 1更早的评论
Davide Masiello
Davide Masiello 2022-4-4
In that case you can replace
[a(i,:),b(i,:)]
with
[a(:,i),b(:,i)]
so each output of myfun is stored as a column in the matrices a and b.
Lev Mihailov
Lev Mihailov 2022-4-4
@Davide Masiello just now I noticed this, and my function returns me the same vector (but changed), but why is it a matrix and not a vector?

请先登录，再进行评论。

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Loops and Conditional Statements 的更多信息

标签

产品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by