Increase time with for loop

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I am trying to create a variable x that increases by 0.5, 16 times. Thus, at i =16, x it should be 8. I keep running into an error of 'Index exceeds the number of array elements. Index must not exceed 1.'
x=[];
x(1)=0;
for i=1:14
x=x(i)+0.5
end

采纳的回答

C B
C B 2022-4-5
编辑:C B 2022-4-5
You want like this or you want array?
x=0;
for i=1:16
x=x+0.5
end
x = 0.5000
x = 1
x = 1.5000
x = 2
x = 2.5000
x = 3
x = 3.5000
x = 4
x = 4.5000
x = 5
x = 5.5000
x = 6
x = 6.5000
x = 7
x = 7.5000
x = 8
y={};
x=0;
for i=1:16
x=x+0.5;
y = [y x];
end
y
y = 1×16 cell array
{[0.5000]} {[1]} {[1.5000]} {[2]} {[2.5000]} {[3]} {[3.5000]} {[4]} {[4.5000]} {[5]} {[5.5000]} {[6]} {[6.5000]} {[7]} {[7.5000]} {[8]}
  3 个评论
Cam B
Cam B 2022-4-5
Can the answer also be represented as a vector? Can you show both forms please. Thank you.
Walter Roberson
Walter Roberson 2022-4-5
x(1)=0;
for i=1:16
x(i+1)=x(i)+0.5
end
x = 1×2
0 0.5000
x = 1×3
0 0.5000 1.0000
x = 1×4
0 0.5000 1.0000 1.5000
x = 1×5
0 0.5000 1.0000 1.5000 2.0000
x = 1×6
0 0.5000 1.0000 1.5000 2.0000 2.5000
x = 1×7
0 0.5000 1.0000 1.5000 2.0000 2.5000 3.0000
x = 1×8
0 0.5000 1.0000 1.5000 2.0000 2.5000 3.0000 3.5000
x = 1×9
0 0.5000 1.0000 1.5000 2.0000 2.5000 3.0000 3.5000 4.0000
x = 1×10
0 0.5000 1.0000 1.5000 2.0000 2.5000 3.0000 3.5000 4.0000 4.5000
x = 1×11
0 0.5000 1.0000 1.5000 2.0000 2.5000 3.0000 3.5000 4.0000 4.5000 5.0000
x = 1×12
0 0.5000 1.0000 1.5000 2.0000 2.5000 3.0000 3.5000 4.0000 4.5000 5.0000 5.5000
x = 1×13
0 0.5000 1.0000 1.5000 2.0000 2.5000 3.0000 3.5000 4.0000 4.5000 5.0000 5.5000 6.0000
x = 1×14
0 0.5000 1.0000 1.5000 2.0000 2.5000 3.0000 3.5000 4.0000 4.5000 5.0000 5.5000 6.0000 6.5000
x = 1×15
0 0.5000 1.0000 1.5000 2.0000 2.5000 3.0000 3.5000 4.0000 4.5000 5.0000 5.5000 6.0000 6.5000 7.0000
x = 1×16
0 0.5000 1.0000 1.5000 2.0000 2.5000 3.0000 3.5000 4.0000 4.5000 5.0000 5.5000 6.0000 6.5000 7.0000 7.5000
x = 1×17
0 0.5000 1.0000 1.5000 2.0000 2.5000 3.0000 3.5000 4.0000 4.5000 5.0000 5.5000 6.0000 6.5000 7.0000 7.5000 8.0000

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