How to stop from rounding off the decimal numbers?

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Virtualkeeda
Virtualkeeda 2015-1-4
回答： Virtualkeeda 2015-1-4
Hi,
if yupperleft(j)== piinterval(i) upperleft(i)= x1(j);
In the above code, yupperleft is the array which i have calculated by some formulation. piinterval is the array generated from : piinterval=(0:0.1:1);
Matlab is storing the value at 31 index of yupperleft as 0.1000. piinterval(2) will also be 0.1000.
But when comparing they are not getting equal. The reason is because yupperleft is actually 0.0999999999999999.
Is there any way so that i can round off or do something so that 0.0999999999999999 gets to 0.1000 actually not just for to show.
Thanks

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采纳的回答

Image Analyst
Image Analyst 2015-1-4
Use tolerances to compare floating point numbers. See the FAQ for code samples and an explanation: http://matlab.wikia.com/wiki/FAQ#Why_is_0.3_-_0.2_-_0.1_.28or_similar.29_not_equal_to_zero.3F

更多回答（2 个）

Stephen23
Stephen23 2015-1-4
编辑：Stephen23 2015-1-4
The simplest method is to allow for some tolerance in the comparison:
A = 0.1;
B = 0.09999999;
Instead of
A==B
you should use
abs(A-B) < 1e-6 % pick this value to suit your needs
Virtualkeeda
Virtualkeeda 2015-1-4
Thank you so much @Image Analyst and @Stephen Cobeldick . The tolerance method worked.
Thank you @Star Strider yours roundn method is also working.

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