Function not giving an output

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Eric Brown
Eric Brown 2022-4-10
回答： Voss 2022-4-10
The code I have is to find the cost of a parking bill. I want the code to return an error message if the inputs are not within my parameters but when I run it, there is not output. pt is a deliniation between long term and short term parking and time is suppose to be a 4 element row vector.
function y = Parking_Bill(pt,time)
if (pt == (1 || 2) && (size(time) == 4))
w = time(1);
d = time(2);
h = time(3);
m = time(4);
if pt == 1
if d>7
weeks = (d/7);
w_fixed = fix(weeks)+ w;
d_fixed = round(rem(d,7));
else
w_fixed = w;
d_fixed = d;
end
if h>24
days= (h/24);
d_fixed= fix(days);
h_fixed = rem(h,24)*24;
else
h_fixed = h;
end
if m > 60
hours = m/60;
h_fixed = fix(hours);
end
if w_fixed >= 1
weekly_bill= 50 * w_fixed;
else
weekly_bill = 0;
end
if d_fixed>=1
daily_bill = 8* d_fixed;
else
daily_bill=0;
end
if h_fixed >= 1
hourly_bill = 2+ (h_fixed-1);
else
hourly_bill = 0;
end
total_bill = weekly_bill + daily_bill + hourly_bill;
y = fprintf('Total bill =$%d.00', total_bill);
if pt == 2
if w > 0
weeks_to_minutes = (w * 10080);
end
if d > 0
days_to_minutes = (d * 1440);
end
if h > 0
hours_to_minutes = (h * 60);
end
if m > 30
minutes = (m/20);
m_fixed= fix(minutes) * 2;
else
m_fixed = 0;
end
total_bill = weeks_to_minutes + days_to_minutes + hours_to_minutes + m_fixed;
y = fprintf('Total bill =$%d.00', total_bill);
else
y = fprintf('Invaild input, check input');
return;
end
end
end
end
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the cyclist
the cyclist 2022-4-10
Rephrasing @KSSV's question:
Can you give specific examples of valid and invalid inputs?

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采纳的回答

Voss
Voss 2022-4-10
function y = Parking_Bill(pt,time)
% if (pt == (1 || 2) && (size(time) == 4))
if (pt == 1 || pt == 2) && numel(time) == 4
w = time(1);
d = time(2);
h = time(3);
m = time(4);
if pt == 1
% calculate total_bill for pt == 1
% fprintf returns the number of bytes printed. you don't want
% that. use sprintf to return the actual character vector printed
% y = fprintf('Total bill =$%d.00', total_bill);
y = sprintf('Total bill =$%d.00', total_bill);
% if pt == 2
elseif pt == 2
% calculate total_bill for pt == 2
% y = fprintf('Total bill =$%d.00', total_bill);
y = sprintf('Total bill =$%d.00', total_bill);
else
% in this case sprintf/fprintf is not necessary
% (nothing formatted in y)
% y = fprintf('Invaild input, check input');
y = 'Invalid input (pt), check input';
% return is not necessary here since the function is about to
% return anyway (i.e., there's no more code to execute in this
% case)
% return;
end
% end
else
% need to return some output y in case pt is not 1 and not 2,
% or t does not have 4 elements
y = 'Invalid input (pt and/or time), check input';
end % end if (pt == 1 || pt == 2) && numel(t) == 4
end % end function

更多回答（1 个）

the cyclist
the cyclist 2022-4-10
编辑：the cyclist 2022-4-10
This condition almost certainly does not do what you expect:
(pt == (1 || 2) && (size(time) == 4))
The problem here is (at least) two-fold. The expression
(1||2)
is going to just evaluate to true. Then you are asking if
pt == true
which presumably is not what you mean. I think you want
(pt==1)||(pt==2)
Also,
size(time)
is always going to be a two-element vector -- row count and column count, so you are going to get a two-element vector from that expression.

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