how to take an alternating range of elements from a vector to make two new vectors

Question

Ali Albaidhani 2022-4-12

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1694925-how-to-take-an-alternating-range-of-elements-from-a-vector-to-make-two-new-vectors

评论： Voss 2022-4-13

采纳的回答： Voss

Hello everyone,

I will try to explain the title with an example.

So let's say i have a vector (a 1x100)

a = [ 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0 0 0]

i want to extract only the 1s and the 0s in new vectors. so we will have two 1x50 vectors

a_1=[ 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1]

a_0=[ 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0]

is there a way to do that in matlab?

regards

Ali

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Answer 1

Voss 2022-4-12

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1694925-how-to-take-an-alternating-range-of-elements-from-a-vector-to-make-two-new-vectors#answer_941300

编辑：Voss 2022-4-12

在 MATLAB Online 中打开

a = [ 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0 0 0];
a_1 = a(a == 1); % elements of a where a equals 1
a_0 = a(a == 0); % elements of a where a equals 0
disp(a_1);
  Columns 1 through 37

     1     1     1     1     1     1     1     1     1     1     1     1     1     1     1     1     1     1     1     1     1     1     1     1     1     1     1     1     1     1     1     1     1     1     1     1     1

  Columns 38 through 50

     1     1     1     1     1     1     1     1     1     1     1     1     1
disp(a_0);
  Columns 1 through 37

     0     0     0     0     0     0     0     0     0     0     0     0     0     0     0     0     0     0     0     0     0     0     0     0     0     0     0     0     0     0     0     0     0     0     0     0     0

  Columns 38 through 50

     0     0     0     0     0     0     0     0     0     0     0     0     0