V12(:,:,h)=(((tau2(:,:,h)-tau2R(:,:,h)).^2+((tau3(:,:,h)- tau3R(:,:,h)).^2).^0.5)./7)));

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Namrata Chandel 2022-4-29

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https://ww2.mathworks.cn/matlabcentral/answers/1707880-v12-h-tau2-h-tau2r-h-2-tau3-h-tau3r-h-2-0-5-7

评论： Namrata Chandel 2022-4-29

采纳的回答： Walter Roberson

How to fix its brackets.

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Walter Roberson 2022-4-29

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https://ww2.mathworks.cn/matlabcentral/answers/1707880-v12-h-tau2-h-tau2r-h-2-tau3-h-tau3r-h-2-0-5-7#answer_953505

在 MATLAB Online 中打开

You have a number of "zero-width space" characters in your code, such as immediately before the "=" character. You have to fix that.

S = 'V12(:,:,h)​=(((tau2(:​,:,h)-tau2​R(:,:,h)).​^2+((tau3(​:,:,h)- tau3R(:,:,​h)).^2).^0​.5)./7)));' ;
find(S == 8203)
ans = 1×7
    11    22    33    44    55    74    85
V12(:,:,h)​=(((tau2(:​,:,h)-tau2​R(:,:,h)).​^2+((tau3(​:,:,h)- tau3R(:,:,​h)).^2).^0​.5)./7)));
   1     0 123    4     3      4     32    34    5     4       5     43   2     1   0??

You have two more ) than you have (

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Walter Roberson 2022-4-29

在 MATLAB Online 中打开

V = sqrt(sum( n .* (tau - tauR).^2 ) ./ sum(n))

This assumes that tau and n are both vectors with the same orientation. If they are 2D arrays then you might need to be more specific about which dimension you sum() over.

Namrata Chandel 2022-4-29