Vectors must be the same length
1 次查看(过去 30 天)
显示 更早的评论
Hi, i have following code with an error: Vectors must be the same length, but i think they are all 143x10498 double.
clc
clear all
clear workspace
load('ModellD_DOK_L1.mat')
C = table2array(ModellDL1WSPL);
CC = split(C,[" ",", "]); % double delimiters split
% CC(1:10,1:10) % show first 10 columns of first 10 rows
% ans = 10×10 string array
CCC=strrep(CC,',','.');
CCC=str2double(CCC);
Z = CCC([287:429],[5:2:20999]);
HQ5000 = CCC([1:143],[5:2:20999]);
HQextrem = CCC([430:572],[5:2:20999]);
HQ10000 = CCC([144:286],[5:2:20999]);
Distanz= CCC([1:143],[4:2:20999]);
for i=1:143
if rem(i-1, 5) == 0;
f = figure;
end
sgtitle('WSPL zeitlicher Verlauf Modell D Teil 1');
a(i)=subplot(5, 1, rem(i-1, 5)+1);
hold on;
% [maxHQextrem,indexHQextrem]=max(Hoehe_HQextrem(:,i)- Hoehe_Z(:,i));
% [maxHQ5000,indexHQ5000]=max(Hoehe_HQ5000(:,i)- Hoehe_Z(:,i));
% [maxHQ10000,indexHQ10000]=max(Hoehe_HQ10000(:,i)- Hoehe_Z(:,i));
%str = ['Maximaler Überlauf [m]: HQextrem ',num2str(maxHQextrem),' HQ5000 ',num2str(maxHQ5000),' HQ10000 ',num2str(maxHQ10000)];
%b(i) = annotation('textbox','String',str,'Position',a(i).Position,'Vert','bottom','FitBoxToText','on');
hold on
% annotation('textbox', 'String',str)
p1=plot (Distanz(i,:) , [Z(i,:), HQextrem(i,:), HQ5000(i,:), HQ10000(i,:)]);
title(['Zeit [h] ', num2str(i)]);
grid on
% xline(indexHQextrem,'-','Maximum','LabelOrientation','horizontal')
% xline(indexHQ5000)
% xline(indexHQ10000)
leg=legend(p1,{'Geländehöhe','HQextrem','HQ5000', 'HQ10000'});
title(leg,'WSPL');
newcolors = {'#000000','#7E2F8E','#0000FF','#00FFFF'};
colororder(newcolors)
xlabel('FKM [km]');
ylabel('Höhe über NN [m]');
xticks([770.62 1538.58 2598.14 3716.89 4674.76 5588.47 6625.1 7535.71 8508.76 9476.3 9562.62])
xticklabels({'126','125','124','123','122','121','120', '119', '118', '117', '116'})
% if rem(i-1, 5) == 4
% %saveas(f,sprintf('hours_%d.png',i));
% saveas(f,sprintf('DOK_Links_Arc1_hours_%d.fig',i));
% end
end
Thanks a lot for your time
2 个评论
采纳的回答
更多回答(0 个)
另请参阅
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!