Evaluating a function with Matlab

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Danny Guana
Danny Guana 2022-5-18
评论： Danny Guana 2022-5-18
Hello friends,
Can anyone help me figure out why I am getting an imaginary number in the following code:
I am supposed to get 1.36. I have done the same calculation using my scientific calculator and symbolab and cannot find what the error is in my code.
  1 个评论
KSSV
KSSV 2022-5-18
Ran in:
t = 10 ;
f = -((t-16.82)/5.604)^1.576
f = -0.3223 + 1.3241i
The result is clear, you are taking exponent of a negative number.

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采纳的回答

Stephen23
Stephen23 2022-5-18
编辑：Stephen23 2022-5-18
Ran in:
"Can anyone help me figure out why I am getting an imaginary number in the following code:"
Because you are taking the power of a negative number.
"I am supposed to get 1.36."
The simple, effiicient, MATLAB approach is to use REALPOW:
t = 10 ;
f = realpow(-((t-16.82)/5.604),1.576)
f = 1.3627

更多回答（1 个）

Torsten
Torsten 2022-5-18
编辑：Torsten 2022-5-18
Then you have to program it as
t = 10;
f = sign(t-16.82).*abs((t-16.82)/5.604).^1.576
An expression
x^a
for x<0 is complex-valued.

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