how to perform bitwise logical xor for two matrices having 13 bit binary data each?

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Abirami 2015-1-29

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回答： Dr. Suneetha CH 2020-8-18

I have two cell arrays with each element having 13 bit binary strings. How to perform bitwise XOR for these two cell arrays.

For eg: consider two 3x3 cell arrays A and B

A=  '1011111111011'    '1011111111011'    '1011111111011'
    '1100000111111'    '1100000111111'    '1100000111111'
    '1100000001000'    '1100000001000'    '1100000001000'
B=  '1100001001010'    '1100001001010'    '1100001001010'
    '1011111100010'    '1011111100010'    '1011111100010'
    '1100000001110'    '1100000001110'    '1100000001110'

My desired output is as below

 C=A XOR B
  ie C(1,1)= '1011111111011' XOR  '1100001001010'
     C(1,1)= '0111111011001'

Similarly for all the elements a bitwise XOR should be performed

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Guillaume 2015-1-29

Your example shows two cell arrays containing strings (made up of characters '0' and '1'), not two matrices containing binary data (which is a just numbers)

So, do you have matrices or cell arrays, and do they contain strings or numbers?

Abirami 2015-1-29

Ive edited the qn sir....

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Answer 1

Guillaume 2015-1-29

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编辑：Guillaume 2015-1-29

在 MATLAB Online 中打开

Assuming that what you have are cell arrays of strings, and you want to output a cell array of string as well, this would be one way to do it:

A = {'1011111111011'    '1011111111011'    '1011111111011'
     '1100000111111'    '1100000111111'    '1100000111111'
     '1100000001000'    '1100000001000'    '1100000001000'};
B = {'1100001001010'    '1100001001010'    '1100001001010'
     '1011111100010'    '1011111100010'    '1011111100010'
     '1100000001110'    '1100000001110'    '1100000001110'};
C = cellfun(@(a,b) char((a ~= b) + '0'), A, B, 'UniformOutput', false)

However, I don't really see a reason to operate on strings, when operating on numbers (and keeping it that way) would be much faster:

A = reshape(bin2dec(A), size(A))
B = reshape(bin2dec(B), size(B))
C = bitxor(A, B)

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Guillaume 2015-1-29

编辑：Guillaume 2015-1-29

Hum, are you sure you've run the first two lines (i.e. converted your cell arrays of strings into matrices of numbers)? By the 3rd line, A and B shouldn't be cell anymore.

Rabia Nazli 2017-7-30