how to return indices?
1 次查看(过去 30 天)
显示 更早的评论
Hi,
I have a 3 dimensional data matrix (72*45*2109), and I need to extract all data less than 15. the final output should be a 3d matrix
I used the following lines, but the result is a vector. The point is to return the indices to have 3d matrix.
Any help would be greatly appreciated.
[r,c,v] = ind2sub(size(data),find(data >= 15));
l = data(sub2ind(size(data),r,c,v));
2 个评论
DGM
2022-6-12
编辑:DGM
2022-6-12
You get a vector, because those are the indices of elements that you wanted -- only the indices you wanted.
Arrays need to be rectangular, without holes.
With that restriction, you'll have to decide what you want to fill all the area where there are elements you didn't want. It could be zero, NaN, etc. It's up to you and what the subequent code can accept without causing errors, since neither zero nor NaN are valid indices.
采纳的回答
Dyuman Joshi
2022-6-12
Based on your comment -
%random data
y=randi(30,2,3,4)
z=NaN(2,3,4);
z(y<15)=y(y<15)
更多回答(0 个)
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Creating and Concatenating Matrices 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!