How to pass from a set of points to lines interpolating them?

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Loren99
Loren99 2022-6-12
编辑： Loren99 2022-9-15
Hi everyone! I have obtained the following skeletonization
However, if you zoom, you see that the pink lines are not lines but they are series of rectangles that contain points, like you can see in this figure here below.
I would like to know how to pass from these points (contained in the rectangles) to approximate lines that trace the skeletonization in pink (Maybe there is an approximative interpolation that can do this (?)). Could anyone help me? Thanks in advance
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Loren99
Loren99 2022-6-12
@Matt J yes I would like to apply something like this to my case, can you help me?
Loren99
Loren99 2022-6-12
编辑：Loren99 2022-6-12
@Image Analyst sorry I was wrong to write. They don't have to be straight lines, but lines instead of points (so they can be also curve lines)

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Matt J
Matt J 2022-6-12
编辑：Matt J 2022-6-12
Ran in:
Image=load('codice_opcode.mat').out;
B=bwboundaries(Image); B(1)=[];
imagesc(Image); colormap(gray); axis image;
hold on
for i=1:numel(B)
[x,y]=cellBoundary(Image,B{i});
plot(x,y,'r','LineWidth',2)
end
hold off
zoom(4)
function [x,y]=cellBoundary(BW,b)
sz=size(BW);
Z=false(sz);
Z( sub2ind(sz,b(:,1),b(:,2)) )=1;
Z=imdilate(Z,ones(3))&BW;
b=bwboundaries(Z,'noholes');
[x,y]=deal(b{1}(:,2), b{1}(:,1));
end
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Loren99
Loren99 2022-6-14
编辑：Loren99 2022-6-14
@Matt J thanks. I have a last question; besides this procedure that does what I wanted, is there also a way to obtain in the workspace the [x,y] coordinates of all the cells that compose my sketch? In fact, because of the 'for cicle' I obtain in the workspace only the [x,y] coordinates of the last cell.
Matt J
Matt J 2022-6-14
Just put the output of cellBoundary somewhere convenient, e.g.,
[x{i},y{i}]=cellBoundary(Image,B{i});

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