If statement working partially

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Gonzalo Guerrero
Gonzalo Guerrero 2022-6-21
评论： Voss 2022-6-22
Hi,
I have been havin problems with the following if statment. My data loads in a loop, which will run depending on the if statment. When it comes to the elseif everything run very smoothly, however, when it comes to the if conditions, it doesn't. I tried to put a keyboard afterwards, because the Time variable gave me error, although once the keyboard is placed, I can put the whole if statment and it will work. As soon as i press continue, it doesn't.
Could you help, please? :D
Thank you
while n<=length(DigMark.codes)
if n==length(DigMark.codes)+1
break;
end
while nn<=4
if n==length(DigMark.codes)+1
break;
end
if nn==4
n=n+1;
nn=1;
continue;
end
if DigMark.codes (n) == 65 || DigMark.codes(n)== 67 || DigMark.codes(n)== 68 ||...
DigMark.codes(n)== 69 && DigMark.codes(n+1)~= 88
Times = find(EMG{nn}.times > DigMark.times(n)-.0004& EMG{nn}.times < DigMark.times(n)+.0004);
Times=Times(1);
Time=EMG{nn}.times(Times);
Code= DigMark.codes(n);
ValuesEMG=(EMG{nn}.values(Times:Times+316));
CalibrateEMG=(0-mean(EMG{nn}.values(Times-316:Times)));
ValuesEMG=(ValuesEMG+CalibrateEMG);
P2PEMG= max(ValuesEMG(48:179))-min(ValuesEMG(48:179));
RMSEMG=rms(EMG{nn}.values(Times-316:Times));
.
.
.
nn=n+1;
elseif DigMark.codes(n)==66 || DigMark.codes(n)== 70 || DigMark.codes(n)== 71 && DigMark.codes(n+1)~= 88
times = find(EMG{nn}.times > DigMark.times(n)-.0004& EMG{nn}.times < DigMark.times(n)+.0004);
times=times(1);
Time=EMG{nn}.times(times);
Code= DigMark.codes(n);
ValuesEMG=(EMG{nn}.values(times:times+161));
CalibrateEMG=(0-mean(EMG{nn}.values(times-314:times)));
ValuesEMG=(ValuesEMG+CalibrateEMG);
P2PEMG= max(ValuesEMG(16:end))-min(ValuesEMG(16:end));
RMSEMG=rms(EMG{nn}.values(times-316:times));
.
.
.
nn=nn+1;
else
n=n+1;
nn=1;
end
end
end
  1 个评论
Stephen23
Stephen23 2022-6-22
Replace
x == 65 || x == 67 || x == 68 || x == 69 && y ~= 88
with
ismember(x,[65,67:69]) && y ~= 88

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回答（1 个）

Voss
Voss 2022-6-21
Ran in:
Part of the problem might be the usage of || and &&.
In MATLAB, && takes precedence over ||, so an expression like this:
x == 65 || x == 67 || x == 68 || x == 69 && y ~= 88
is interpreted as this:
x == 65 || x == 67 || x == 68 || (x == 69 && y ~= 88)
but I think you probably mean this:
(x == 65 || x == 67 || x == 68 || x == 69) && y ~= 88
Here's a concrete case where it makes a difference:
x = 65;
y = 88;
disp( x == 65 || x == 67 || x == 68 || x == 69 && y ~= 88 )
1
disp( (x == 65 || x == 67 || x == 68 || x == 69) && y ~= 88 )
0
Another potential problem is that you let n go up to length(DigMark.codes) but then try to access DigMark.codes(n+1).
  2 个评论
Gonzalo Guerrero
Gonzalo Guerrero 2022-6-22
Thanks for your answer!
I considered that too, but It is weird that the line of elseif works, but then the if doesn't...
I have changed the while loop for a for loop instead and now it works perfectly. It might be just the loop wasn't the right one, for some reason I don't know :S
Voss
Voss 2022-6-22
I don't think either line (if or elseif) was working as you probably intended. Maybe the elseif appeared to work for whatever values it happened to get.

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