Applying within range function

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Adnan Jayyousi
Adnan Jayyousi 2022-6-23
回答： Steven Lord 2022-6-23
Ran in:
Hello everyone,
I am trying to check if ceratin days are withing a specific range, using the withinrange function.
The code is :
%% Define date&time arrays :
t1 = datetime(2021,1,1,0,0,0);
t2 = datetime(2021,12,31,23,0,0);
DateNtime = (t1:hours(1):t2)'
DateNtime = 8760×1 datetime array
01-Jan-2021 00:00:00 01-Jan-2021 01:00:00 01-Jan-2021 02:00:00 01-Jan-2021 03:00:00 01-Jan-2021 04:00:00 01-Jan-2021 05:00:00 01-Jan-2021 06:00:00 01-Jan-2021 07:00:00 01-Jan-2021 08:00:00 01-Jan-2021 09:00:00 01-Jan-2021 10:00:00 01-Jan-2021 11:00:00 01-Jan-2021 12:00:00 01-Jan-2021 13:00:00 01-Jan-2021 14:00:00 01-Jan-2021 15:00:00 01-Jan-2021 16:00:00 01-Jan-2021 17:00:00 01-Jan-2021 18:00:00 01-Jan-2021 19:00:00 01-Jan-2021 20:00:00 01-Jan-2021 21:00:00 01-Jan-2021 22:00:00 01-Jan-2021 23:00:00 02-Jan-2021 00:00:00 02-Jan-2021 01:00:00 02-Jan-2021 02:00:00 02-Jan-2021 03:00:00 02-Jan-2021 04:00:00 02-Jan-2021 05:00:00
Holidays = datetime({'2021-03-27';'2021-03-28';'2021-04-02';'2021-04-03';
'2021-04-14';'2021-04-15';'2021-5-16';'2021-05-17';'2021-09-06';'2021-09-07';'2021-09-15';'2021-09-16';'2021-09-20';'2021-09-27'});
rangeOfTimes = timerange(t1,t2);
tf = withinrange(Holidays(1,1), rangeOfTimes);
Check for incorrect argument data type or missing argument in call to function 'withinrange'.
-----
In the "tf" array i am getting argument error. What causes the error ?
Thanks

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采纳的回答

Steven Lord
Steven Lord 2022-6-23
The withinrange function requires its first input to be a timetable, not a datetime array. You probably want isbetween instead.

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