A is a square block matrix of order S which not fixed. pi is a column matrix of order S. How to find the solutions of the system of equations: (pi)A=0, (pi)e=1, e column of 1s

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Abdul Rof V 2022-6-28

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回答： Balaji Udayagiri 2022-6-28

A is a square block matrix of order S which not fixed.Each block has order m π is a column(block) matrix of variables order S. How to find the solutions of the system of equations: πA=0, πe=1, where e is a column vector of 1's of appropriate order

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Answer 1

Balaji Udayagiri 2022-6-28

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Hi Abdul,

As per my understanding, you want to solve the system of linear equations, πA = 0, πe = 1. You can augment the e to the Matrix A, and solve the new set of equations using linsolve().

Here is an example code for your reference:

syms x y z
eqn1 = 2*x + y + z == 0;
eqn2 = -x + y - z == 0;
eqn3 = x + 2*y + 3*z == 0;
eqn4 = x + y + z == 1;
[A,B] = equationsToMatrix([eqn1, eqn2, eqn3, eqn4], [x, y, z]);
X = linsolve(A,B);
disp(X);