How to extract only certain points contained in a segment?
1 次查看(过去 30 天)
显示 更早的评论
Hi everyone. I have the following problem. I have segments with a series of point.
For each segment I would like to consider only the point which is closest to a certain obstacle and then I would like to save these points in an n x 2 array where the first column of this array represents the x-coordinates of the points and the second column of the array represents the y-coordinates of the points. How can I do it?
0 个评论
回答(2 个)
Image Analyst
2022-9-15
Try this, assuming you have your points in x and y, and your obstacle point is in x0, y0:
distances = sqrt((x - x0) .^ 2 + (y - y0) .^ 2);
[sortedDistances, sortOrder] = sort(distances, 'ascend');
Then you can take however many of the "close" points as you want. Like let's say you want the 9 closest points:
sortedx = x(sortOrder);
sortedy = y(sortOrder);
xClosest = sortedx(1 : 9);
yClosest = sortedy(1 : 9);
Or maybe you just want a list of all distances less than 30:
distances = sqrt((x - x0) .^ 2 + (y - y0) .^ 2);
% Get logical indexes of what points are closer than 30.
closeIndexes = distances < 30;
xClosest = x(closeIndexes);
yClosest = y(closeIndexes);
0 个评论
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Computational Geometry 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!