Finding Maximum Consecutive Dry Days in Daily Rainfall Data

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Hi All,
I am trying to find maximum consecutive dry days in a long time series of daily rainfall. I am using a script to do for one year of data. Can somebody help to modify the code such that it counts the Max CDD for each year separately. Whenever the data is less than 0.1, it is considered as dry day.
max_dry = 0; % initialize the maximum number of consecuitive dry days
counter = 0;
for k=1:366
if a(k) == 0
counter = counter + 1;
else
if counter > max_dry
max_dry = counter;
max_dry_position = k - counter;
end
counter = 0;
end
end

采纳的回答

Bjorn Gustavsson
Bjorn Gustavsson 2022-7-5
编辑:Bjorn Gustavsson 2022-7-5
Don't do it with loops, that is a lot of work. Use the vectorized functions to your advantage. Here's how to get at it with using diff and max:
drf = 3*randn(366,1); % mocking up some daily rainfall-data.
DryDayThresh = 0.1;
rdc = find(drf > DryDayThresh); % Find the rainy days
plot(diff(rdc)) % Plot the difference between rainy days, 1 means two consecutive rainy days.
[maxCDD] = max(diff(rdc))-1;
HTH
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更多回答(2 个)

Saksham Gupta
Saksham Gupta 2022-7-5
As per my understanding, you need assistance in writing code for your problem.
This code should be helpful as per the conditions shared by you.
max_dry = 0; % initialize the maximum number of consecuitive dry days
counter = 0;
% a is supposed to be having data of each day as vector, I am using length, as year can
% have either 365 or 366 days.
for k=1:length(a)
if a(k) < 0.1 % conditon as mentioned by you
counter = counter + 1;
else
counter = 0;
end
max_dry=max(counter,max_dry);
end
  1 个评论
Faisal Baig
Faisal Baig 2022-7-5
yes that gives the total number of dry days out of my data. But I need the Max Consecutive Dry Days (CDD) for each individual year.

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Walter Roberson
Walter Roberson 2022-7-5
This code shows one way of finding all the runs of maximum length.
rng(12345)
drf = rand(366,1); % mocking up some daily rainfall-data.
DryDayThresh = 0.2;
drf = reshape(drf, 1, []); %need it to be a row vector
rdc = drf < DryDayThresh; % locate the dry days
starts = strfind([0 rdc], [0 1]);
stops = strfind([rdc 0], [1 0]);
durations = stops - starts + 1;
longest = max(durations)
longest = 3
long_idx = durations == longest;
start_of_longest = starts(long_idx)
start_of_longest = 1×2
234 345
end_of_longest = stops(long_idx)
end_of_longest = 1×2
236 347
plot(drf);
yline(DryDayThresh)
hold on
%stairs(rdc, 'k')
xline(start_of_longest, 'r')
xline(end_of_longest, 'r')
  1 个评论
Walter Roberson
Walter Roberson 2022-7-5
rng(12345)
drf = rand(366,1); % mocking up some daily rainfall-data.
DryDayThresh = 0.2;
drf = reshape(drf, 1, []); %need it to be a row vector
rdc = drf < DryDayThresh; % locate the dry days
props = regionprops(rdc, 'BoundingBox', 'Area');
durations = [props.Area];
longest = max(durations);
long_idx = durations == longest;
selected_props = props(long_idx);
bounds_of_longest = round(vertcat(selected_props.BoundingBox) + [.5 .5 0 0]);
start_of_longest = bounds_of_longest(:,1)
start_of_longest = 2×1
234 345
end_of_longest = start_of_longest + bounds_of_longest(:,3) - 1
end_of_longest = 2×1
236 347
plot(drf);
yline(DryDayThresh)
hold on
xline(start_of_longest, 'r')
xline(end_of_longest, 'r')

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