Error in concatination in binary values

6 次查看（过去 30 天）
lilly lord
lilly lord 2022-7-7
评论： Stephen23 2022-7-8
Hi, I am trying to concatinate the two 4-bit binary values to get 8 -bit value and then I have to convert it into decimals. But I am getting few errors. The sample code is given below
c1=[8 14 10 9 6 3 2 7 6 11 6 3 13 15 6 0];
NewR=[];
for i=1:2:length(c1)
n1=de2bi(c1(i),'left-msb');
n2=de2bi(c1(i+1),'left-msb');
result = [n1 n2];
NewR(i)=bi2de(result,'left-msb');
end
NewR
Required output =[ 142 169 99 39 107 99 223 96] % for example the last two digits 6 and 0 when written in binary gives 0110 0000 =96
what I am getting is
NewR =
142 0 169 0 27 0 23 0 107 0 27 0 223 0 12
  1. how to remove zeros in between the values.
  2. Few values are correct but some are wrong.

请先登录，再回答此问题。

采纳的回答

Stephen23
Stephen23 2022-7-7
Ran in:
V = [8,14,10,9,6,3,2,7,6,11,6,3,13,15,6,0];
N = bin2dec(reshape(dec2bin(V,4).',8,[]).')
N = 8×1
142 169 99 39 107 99 223 96

更多回答（1 个）

James Tursa
James Tursa 2022-7-7
Ran in:
c1=[8 14 10 9 6 3 2 7 6 11 6 3 13 15 6 0];
NewR = c1(1:2:end)*16 + c1(2:2:end)
NewR = 1×8
142 169 99 39 107 99 223 96
  1 个评论
Stephen23
Stephen23 2022-7-8
Ran in:
V = [8,14,10,9,6,3,2,7,6,11,6,3,13,15,6,0];
N = [16,1]*reshape(V,2,[])
N = 1×8
142 169 99 39 107 99 223 96

请先登录，再进行评论。

类别

在 Help Center 和 File Exchange 中查找有关 Environment and Settings 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by