To find n number of histcounts in a loop

Question

SP 2022-7-14

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1759555-to-find-n-number-of-histcounts-in-a-loop

评论： KSSV 2022-7-14

Hi,

I am having a cell array (c) of 3000*2 cell, each containing 1*1000 matrix values. Here I need to find histcounts of each cell and concatenate horizontally. I have used following code to calculate individually, but I need to do for all 3000*2 cell in a loop and store it in a separate cell array (z) of dimension 3000*30. (since bin count is 15 for each column).

[N{1},edges{1}] = histcounts(c{1,1},15); % bin count=15 % column 1
[N{2},edges{2}] = histcounts(c{1,2},15); % column 2
z = horzcat(N{1,1}, N{1,2}); %horizontal concatenation

How can I do this? Kindly help me with this. Thanks in advance.

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

KSSV 2022-7-14

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1759555-to-find-n-number-of-histcounts-in-a-loop#answer_1006950

编辑：KSSV 2022-7-14

在 MATLAB Online 中打开

z = cell2mat(N) ;

Or

z = [N{:}] ;

4 个评论
显示 2更早的评论隐藏 2更早的评论

SP 2022-7-14

By using this I am able to find only a single row of c{1,1} and c{1,2}. I need to find for all 3000*2 cell in a loop.

KSSV 2022-7-14

在 MATLAB Online 中打开

Are you looking for?

[m,n] = size(c) ; 
z = cell(m,1) ; 
for i = 1:m
    [N{1},edges{1}] = histcounts(c{i,1},15); % bin count=15 % column 1
    [N{2},edges{2}] = histcounts(c{i,2},15); % column 2
    z{i} = horzcat(N{1,1}, N{1,2}); %horizontal concatenation
end