How to find column where 0 turns to 1 for each row
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Hello!
I would like to be able to find the column (or column title) for each row where the 0 turns to 1.
I have attached example rows (egcolumnsep.mat), so for example for row 5, I would like it to return column 20 (or Bins_11). I would like an output for all the rows though. Some rows might have only 0's (this can be NaN). This basically gives me the reaction time for each row.
Thank you for your help! =)
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采纳的回答
Bruno Luong
2022-7-15
编辑:Bruno Luong
2022-7-15
load('egcolumnsep.mat');
c1 = find(strcmp(DATAb1.Properties.VariableNames,'Bins_1')); % == 10
% Extract relevant data
A = table2array(DATAb1(:,c1:end));
if ~all(ismember(A,[0 1]),'all')
error('Data must be 0 or 1')
end
[cols,rows] = find(diff(A.')==1);
cols = cols+c1;
Idx01 = table(rows,cols)
2 个评论
Bruno Luong
2022-7-15
编辑:Bruno Luong
2022-7-15
Why didn't tell us that you are interested only the first transition in the question?
You can call this statement after the above scriot
groupsummary(Idx01, 'rows','min')
or start from scratch
load('egcolumnsep.mat');
c1 = find(strcmp(DATAb1.Properties.VariableNames,'Bins_1')); % == 10
% Extract relevant data
A = table2array(DATAb1(:,c1:end));
if ~all(ismember(A,[0 1]),'all')
error('Data must be 0 or 1')
end
[a,cols] = max(A,[],2);
cols = (cols+c1-1) .* (a==1) % returns 0 if no transition 0->1 is found
更多回答(1 个)
Jonas
2022-7-14
编辑:Jonas
2022-7-14
yourMat=[0 0 0 0 0;
0 1 1 0 0;
0 0 0 1 0];
where=arrayfun(@(idx)find(diff(yourMat(idx,:))==1,1,'first')+1,1:size(yourMat,1),'UniformOutput',false)'
an empty cell shows that there was not such a change
you could set it to NaN and convert to an normal array by
where{cellfun('isempty',where)}=NaN
where=cell2mat(where)
3 个评论
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