How to declare a function having bounds ?
显示 更早的评论
example-
f(x)= 0 x<0
x 0<x<1
-1 x>1
2 个评论
David Young
2015-2-9
编辑：David Young
2015-2-9
What is supposed to happen if x=0 or x=1? I'm guessing you mean
0 if x < 0
x if 0 <= x <= 1
-1 if x > 1
David Webb
2015-2-9
采纳的回答
One way,
f=@(x) x.*(x>=0 & x<=1) - (x>1)
更多回答（2 个）
David Young
2015-2-9
I would go for a vectorised function:
function x = clipZeroOne(x)
x(x < 0) = 0;
x(x > 1) = -1;
end
Test examples
clipZeroOne(9)
clipZeroOne(0.5)
clipZeroOne(-0.5)
clipZeroOne([-Inf -3 0 0.2 0.9 1 15 Inf]) % apply to a vector
function f=fcn(x)
if x<0
y = 0;
else if x>=0 && x<1
y = x;
else if x>1
y = -1;
end
In the example f(0) = x.
2 个评论
David Webb
2015-2-9
David Young
2015-2-9
编辑：David Young
2015-2-9
This answer has multiple issues, as they like to say on Wikipedia.
- What happens if x is exactly equal to 1?
- The output variable is f but you assign the result to y.
- "else if" isn't legal MATLAB.
- The "{} Code" button makes the code display clearly.
I guess what you meant was this
function y = fcn(x)
if x<0
y = 0;
elseif x<1 % it must be greater than or equal to 0
y = x;
else
y = -1; % it must be greater than or equal to 1
end
end
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