how to delete particular values in this matrix ?

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Matlab111 2015-2-9

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评论： Matlab111 2015-2-10

 [a b]=[     0.5708    0.0755         0         0         0         0         0
                  0         0  161.5569         0   84.9907   35.0193   17.0669];

i don't want the values before this

" 0
  0 "

and my answer should be like this..

 [c d]=[ 0         0         0         0
         0   84.9907   35.0193   17.0669];

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Michael Haderlein 2015-2-9

编辑：Michael Haderlein 2015-2-9

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That's quite a lot of code for this question (and most of the code has nothing to do with the question). What is the criterion? Should everything be deleted until a column of zeros? Should the first three columns be deleted? Or is it something else?

case 1: (what Image Analyst was hinting at)

a=[ 0.5708    0.0755    0           0   0         0         0;
    0         0         161.5569    0   84.9907   35.0193   17.0669];
allzeros=find(all(a==0));
b=a(:,allzeros:end);

case 2:

b=a(:,4:end);

If none of these cases are what you're looking for, please give detailed information on what you need and post only relevant code.

Matlab111 2015-2-9

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Michael Haderlein- sir, don't go for code just see below i given some example.

question:

c=[0.7893 0.8337 0.1479 0 0 0.1479 0.9993];

1.now i should delete the repeated values in that 'c'.

2.i should delete the values that is displayed before the zeros.

3.And finally i should delete zeros also.

Expected output:

d=[0.9993];

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Stephen23 2015-2-10

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To solve your (constantly changing) requirement stated in your last comment to my original answer, try this code:

allR111 = [allR11;allR21];
Y3 = true(1,size(allR111,2));
Y3(1:find(abs(allR111(1,:))<1e-6,1,'last')) = false;
Y3(1:find(abs(allR111(2,:))<1e-6,1,'last')) = false;
allR111(:,Y3)

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Matlab111 2015-2-10

Stephen Cobeldick- really thanks sir, you helped me a lot

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Stephen23 2015-2-9

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https://ww2.mathworks.cn/matlabcentral/answers/176676-how-to-delete-particular-values-in-this-matrix#answer_167484

编辑：Stephen23 2015-2-9

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Try this:

>> c = [0.7893,0.8337,0.1479,0,0,0.1479,0.9993];
>> X = sum(bsxfun(@(a,b)abs(a-b)<1e-6,c(:).',c(:)))<2;
>> X(1:find(c==0,1,'last')) = false;
>> c(X)
ans =  0.9993

As in my answer to your other related question , note that I did not use equality test == or unique with floating point numbers, but instead compared the difference of two values with some tolerance, in this case 1e-6. You can change the tolerance to best suit your problem.

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Matlab111 2015-2-9

编辑：Matlab111 2015-2-9

Stephen Cobeldick- sir, i try your logic with my main code ya i'm getting but, actually i want to get like this, just see below... when "r=0" i'm getting correct values that's what i expected but when "r=1" i'm not getting an expected values.