how to delete particular values in this matrix ?
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[a b]=[ 0.5708 0.0755 0 0 0 0 0
0 0 161.5569 0 84.9907 35.0193 17.0669];
i don't want the values before this
" 0
0 "
and my answer should be like this..
[c d]=[ 0 0 0 0
0 84.9907 35.0193 17.0669];
6 个评论
Michael Haderlein
2015-2-9
编辑:Michael Haderlein
2015-2-9
That's quite a lot of code for this question (and most of the code has nothing to do with the question). What is the criterion? Should everything be deleted until a column of zeros? Should the first three columns be deleted? Or is it something else?
case 1: (what Image Analyst was hinting at)
a=[ 0.5708 0.0755 0 0 0 0 0;
0 0 161.5569 0 84.9907 35.0193 17.0669];
allzeros=find(all(a==0));
b=a(:,allzeros:end);
case 2:
b=a(:,4:end);
If none of these cases are what you're looking for, please give detailed information on what you need and post only relevant code.
采纳的回答
Stephen23
2015-2-10
To solve your (constantly changing) requirement stated in your last comment to my original answer, try this code:
allR111 = [allR11;allR21];
Y3 = true(1,size(allR111,2));
Y3(1:find(abs(allR111(1,:))<1e-6,1,'last')) = false;
Y3(1:find(abs(allR111(2,:))<1e-6,1,'last')) = false;
allR111(:,Y3)
更多回答(1 个)
Stephen23
2015-2-9
编辑:Stephen23
2015-2-9
Try this:
>> c = [0.7893,0.8337,0.1479,0,0,0.1479,0.9993];
>> X = sum(bsxfun(@(a,b)abs(a-b)<1e-6,c(:).',c(:)))<2;
>> X(1:find(c==0,1,'last')) = false;
>> c(X)
ans = 0.9993
As in my answer to your other related question , note that I did not use equality test == or unique with floating point numbers, but instead compared the difference of two values with some tolerance, in this case 1e-6. You can change the tolerance to best suit your problem.
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