help me.. how to fix this error. and run this prog. i need to put 2 variables in equations and get answers. so i took a range and a random number generater. is there any other way?

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ABHISEK MOHANTY
ABHISEK MOHANTY 2015-2-9
评论： Star Strider 2015-2-9
clc
clear all
n=[1:.001:7];
d=rand(1000,1);
%display(n)
[a]=d*n;
% display([a])
[p]= (2*pi*[a]*cos(45))/300;
%display([p])
[A]=cos(p);
%display([A])
[B]=(1i.*sin(p)/n);
%display([B])
[C]=1i.*n.*sin(p);
%display([C])
[D]=cos(p);
%display([D])
%Reflection coefficient
[r]=real((n(1).*[A]+n(1).*n(3).*[B]+[C]-n(3).*[D])./(n(1).*[A]+n(1).*n(3).*[B]+[C]+n(3).*[D]));
%display ([r])
%[t]=(2.*n(1))./(n(1).*[A]+n(1).*n(3).*[B]+[C]+n(3).*[D]);
%display([t])
f=([r].^2)*100;
display(f)

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回答（1 个）

Image Analyst
Image Analyst 2015-2-9
In the line:
[C]=1i.*n.*sin(p);
n is 1-by-6001 and sin(p) is 1000-by-6001. To use .* the arrays must be the same size. I didn't delve into the code so I don't know what your intent here is. Maybe you want * instead of .* to do a matrix multiplication???
  1 个评论
ABHISEK MOHANTY
ABHISEK MOHANTY 2015-2-9
编辑：ABHISEK MOHANTY 2015-2-9
i want to take range of n as 1 to 7 and d as 1 to 100 for atleast 1000 values and gets answers some how. can u help me? main part is the range n and d needs to work and get values for the [a], which will get answers for rest equations. i am new to matlab. so if there is any other way to write program, please say so.

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