How to find the value from equations?

3 次查看(过去 30 天)
Hi all,
I have a dataset (Ids) and equestion as the attachment.
Ids = [6.35E-06
6.18E-06
6.01E-06
5.84E-06
5.68E-06
5.52E-06
5.36E-06
5.20E-06
5.05E-06
4.89E-06
4.75E-06
4.60E-06
4.45E-06
4.31E-06
4.17E-06
4.03E-06
3.90E-06
3.76E-06
3.63E-06
3.50E-06
3.38E-06
3.25E-06
3.13E-06
3.01E-06
2.90E-06
2.78E-06
2.67E-06
2.56E-06
2.45E-06
2.35E-06
2.25E-06
2.15E-06
2.05E-06
1.95E-06
1.86E-06
1.77E-06
1.68E-06
1.60E-06
1.51E-06
1.43E-06
1.35E-06
1.28E-06
1.20E-06
1.13E-06
1.06E-06
9.95E-07
9.30E-07
8.68E-07
8.08E-07
7.50E-07
6.95E-07
6.41E-07
5.90E-07
5.41E-07
4.95E-07
4.51E-07
4.09E-07
3.69E-07
3.31E-07
2.95E-07
2.62E-07
2.31E-07
2.02E-07
1.75E-07
1.50E-07
1.27E-07
1.06E-07
8.77E-08
7.09E-08
5.60E-08
4.31E-08
3.20E-08
2.28E-08
1.52E-08
9.39E-09
5.11E-09
2.28E-09
7.14E-10
1.12E-10
6.28E-12
2.10E-13
6.54E-15
3.27E-16
-2.03E-16
-2.06E-16
4.78E-16
3.29E-16
-3.03E-16
4.10E-16];
where, the Wg = 6; Lg = 2.3;
may I know how to obtain the Ids'?
Here, I set Ids' = a , and code as following:
Wg = 6;
Lg = 2.3;
syms a
eqn = (1*10^(-5)).*(Wg./Lg)* log10( 1 + exp(a./5)) ./ ( 1 + exp(a./5))==Ids
S = solve(eqn);
S
when I click the run, it seems no response. Does this approach is correct?

采纳的回答

Walter Roberson
Walter Roberson 2022-8-5
eqn = (1*10^(-5)).*(Wg./Lg)* log10( 1 + exp(a./5)) ./ ( 1 + exp(a./5))==Ids
IDS is a vector, so eqn is a vector. But syms a is a scalar symbolic variable.
S = solve(eqn);
You are asking to solve the vector of equations for the single scalar value for a that solves all of the equations simultaneously. That is not going to exist.
Are you looking for "best fit" or are you looking to solve each of the equations independently ?
  3 个评论
Chuanjung Lin
Chuanjung Lin 2022-8-5
Hi Roberson,
First of all, thank you for your feedback quickly. Acutally, I'm doing the ANN modeling. Because the Ids has large dynamic range from 4.1E-16 to 6.35E-6. So, I've to preproecess the Ids data for accurancy improvment. And I plan used the preproecess that paper mentioned. But, I don't know how to conduct it (Transfer the measurement Ids to Ids'). Thank you.
Walter Roberson
Walter Roberson 2022-8-8
Are you looking for "best fit" or are you looking to solve each of the equations independently ? The code I posted shows the best fit in a least-squares sense. If you want to solve each individually then loop or use arrayfun.

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Mathematics and Optimization 的更多信息

标签

产品


版本

R2020b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by