split columns with separate elements

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Dion Theunissen
Dion Theunissen 2022-8-10
编辑： Chetan 2023-9-7
I have a column with lastnames and insertions. How can i split those? Cause not all the lastnames have the same number of elements.
a = bookings.child_firstname
b = split(a,' ')
Now I have the following error:
Error using split
Element 8 of the text contains 1 matches while the previous elements
have 0. All elements must contain the same number of matches.
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Walter Roberson
Walter Roberson 2022-8-10
regexp(a, '\s+', 'split')
would return a cell array with one entry for each a entry, with the cell array entry being a cell array of character vectors (or possibly a string array?)
dpb
dpb 2022-8-10
One could also investigate the new(ish) pattern object/function that has "regexp for dummies" kind of functionality...

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回答（1 个）

Chetan
Chetan 2023-9-6
编辑：Chetan 2023-9-7
Ran in:
Hello @Dion Theunissen,
I understand that you are currently facing an issue while using the “split” function due to unequal sizes of the spitted array.
The“split”function in MATLAB requires that all elements in the input text have the same number of matches. In your case, since the last names and insertions have varying lengths, the“split”function cannot be directly used.
To split last names and insertions that have varying lengths, you can use regular expressions and the“regexp”function in MATLAB. Regular expressions provide a flexible way to match patterns in text.
You can refer to the documentation of these functions below:
Here's an example of how you can split last names and insertions using regular expressions:
% Example input
lastNames = {'Smith', 'Johnson Jr.', 'Brown III', 'Davis'};
% Initialize arrays to store last names and insertions
splitLastNames = cell(size(lastNames));
insertions = cell(size(lastNames));
% Regular expression pattern to match last names and insertions
pattern = '^(.*?)\s+(.*?)$';
for i = 1:numel(lastNames)
% Match the pattern using regular expressions
matches = regexp(lastNames{i}, pattern, 'tokens');
if isempty(matches)
% No insertion found, assign the whole string as the last name
splitLastNames{i} = lastNames{i};
insertions{i} = '';
else
% Extract the last name and insertion from the matches
splitLastNames{i} = matches{1}{1};
insertions{i} = matches{1}{2};
end
end
% Display the split last names and insertions
for i = 1:numel(lastNames)
disp(['Last Name: ' splitLastNames{i} ', Insertion: ' insertions{i}]);
end
Last Name: Smith, Insertion: Last Name: Johnson, Insertion: Jr. Last Name: Brown, Insertion: III Last Name: Davis, Insertion:
In this example, the regular expression pattern“^(.*?)\s+(.*?)$”is used to match the last name and insertion. The“^”and“$”symbols denote the start and end of the string, respectively. The“(.*?)”captures any characters lazily (i.e., as few as possible), and“\s+”matches one or more whitespace characters.
I hope these suggestions help you resolve the issue you are facing.
Best regards
Chetan Verma

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