Caesar cipher matlab code

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Can anyone write a very basic code for caesar cipher that shifts input characters by 5 place?
  1 个评论
James Tursa
James Tursa 2022-8-25
What have you done so far? What specific problems are you having with your code?

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采纳的回答

Md. Atiqur Rahman
Md. Atiqur Rahman 2022-8-27
编辑:Walter Roberson 2022-8-28
%% To whom it may concern
Plaintext= input('Plaintext: ','s')
Shift= input('Shift: ')
Output = Plaintext+Shift;
r=Output-26;
for i = 1:length(Plaintext)
if Output(i) <= 90
Output(i) = char(Output(i));
else
Output(i) = char(r(i));
end
end
fprintf('Ciphertext: ','s')
disp(char(Output))
  10 个评论
Md. Atiqur Rahman
Md. Atiqur Rahman 2022-8-31
I think I've done it better 😎
Walter Roberson
Walter Roberson 2022-8-31
Output(i) = char(Output(i));
Why are you doing that redundant operation? Yes, you convert to char but you store it in the same array so it would convert back to the same data type.
Output(Output<=58)=32;
Why are you mixing logical indexing of the entire array inside a loop?

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更多回答(1 个)

Walter Roberson
Walter Roberson 2022-8-25
cc5('HELLO')
ans = 'MJQQT'
cc5('ABCXYZ')
ans = 'FGHCDE'
function out = cc5(in)
TT('A':'Z') = ['F':'Z', 'A':'E'];
out = TT(in);
end
  2 个评论
Md. Atiqur Rahman
Md. Atiqur Rahman 2022-8-27
编辑:Walter Roberson 2022-8-27
Plaintext= input('Plaintext: ','s')
Shift= input('Shift: ')
if Plaintext+Shift <= 90
Ciphertext = (char(Plaintext+Shift))
else
Ciphertext = (char(Plaintext+Shift-26))
end
%Can you fix this?
Walter Roberson
Walter Roberson 2022-8-27
Your Plaintext is a vector of characters. Plaintext+Shift <= 90 would be a vector. When you if a vector, the result is considered true only if all of the values in the vector are non-zero. So your Plaintext+Shift <= 90 test would be true only if all of the characters where no more than 'U'
You should investigate logical indexing.

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