Least square magnitude solution

2 次查看（过去 30 天）
Cesar Cardenas
Cesar Cardenas 2022-8-28
评论： Cesar Cardenas 2022-8-28
is this a right approach to calculate the least square magnitude x* to this problem? Any help will be greatly appreciated. Thanks
A = [1 2 3 4 5; 6 7 8 9 0];
b = [1;2];
x = lsqr(A,b)
e2 = b - A*x
norm(e2)

请先登录，再回答此问题。

采纳的回答

Torsten
Torsten 2022-8-28
编辑：Torsten 2022-8-28
Ran in:
A = [1 2 3 4 5; 6 7 8 9 0];
b = [1;2];
x = lsqminnorm(A,b).'
x = 1×5
0.0400 0.0560 0.0720 0.0880 0.0560
norm(x)
ans = 0.1442
norm(A*x.'-b)
ans = 0
if you search for the solution for which x has minimum norm.
If you only search for an arbitrary least-squares solution (i.e. for an x for which norm(e2) is minimum), simply use
x = (A\b).'
x = 1×5
0 0 0 0.2222 0.0222
norm(x)
ans = 0.2233
norm(A*x.'-b)
ans = 2.2204e-16

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Performance and Memory 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by