How to create an if loop with conditions

Question

GB92_R 2022-8-28

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https://ww2.mathworks.cn/matlabcentral/answers/1789205-how-to-create-an-if-loop-with-conditions

评论： GB92_R 2022-8-28

Hi,

in my Time analysis i need to divide my vector 'pupil diameter' in 3 moments and for each one i have to calculate the median

and i did it in this way

%% TIME SPAN ANALYSIS 
time_1 = median(diametre(1:33000));
time_2 = median(diametre(33001:66000));
time_3 = median(diametre(66001:99000));

but not all my subject have vector length which reaches 99000 timestamps so i created a loop where i wrote:

for i=1:length(list)
    time_1 = median(diametre(1:33000));
    time_2 = median(diametre(33001:66000));
    if diametre > 66000
        time_3 = median(diametre(66001:99000));
    end

list is the list of my participant. When it comes to calculate time_3 then it tell me that the matrix exceed the dimension so it means that the loop doesnt work despite i check the length of the signal in all my participant before choosing where to cut

can you please help me write it correctly?

thank you very much in advance