Attach new values to a matrix during loop and then get the integral with cumtrapz command

Question

Dennis 2022-8-31

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1791815-attach-new-values-to-a-matrix-during-loop-and-then-get-the-integral-with-cumtrapz-command

评论： Shree Charan M L 2023-10-11

在 MATLAB Online 中打开

Hey there,

a matrix should be initialized and filled with values of time, a signal value and the corresponding integral.

the variable "stepcounter" functions as a control variable to identify when the step threshold is violated. Each step the corresponding integral should be calculated and in the end be added together to finally get a plot of the integral over the time values. However the time values are not steady, hence the thought of the stepcounter. A matrix is defined and should be filled with the right values for the right counter value.

Below you can find the code and I hope you can help me!

i=0;
step = 60; 
stepcounter = 1;
for i=2:(length(tay))
   
    if (Integ_MTRX(i, 1)-Integ_MTRX((i-1),1)) > step
        stepcounter = stepcounter +1;
        Integ_MTRX(i,3) = stepcounter;
    else
        Integ_MTRX(i,3) = stepcounter;
    end
end 
for i=1:(stepcounter)
    clear temp;
    temp = Integ_MTRX(Integ_MTRX(:,3)==i,:);
   
    B(:,i) = temp(:,1); 
    B(:,i+1) = temp(:,2); 
    B(:,i+2) = cumtrapz(temp(:,1),temp(:,2));
    if stepcounter < 1
    B(length(B(:,1))+1:length(B(:,1))+length(temp(:,1)),i) = temp(:,1);
    B(length(B(:,2))+1:length(B(:,2))+length(temp(:,2)),i) = temp(:,2);
    B(length(B(:,3))+1:length(B(:,3))+length(temp(:,3)),i) = cumtrapz(temp(:,1),temp(:,2));
    end
end