Trying to use 'parfor', but it is very slow

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Lee Hwihyeong
Lee Hwihyeong 2015-2-20
评论： Adam 2015-2-20
Hello, I am trying to use parfor as below.
-------------------------
parpool(2)
A=zeros(10,10);
for iX=1:10
parfor iY=1:10
A(iY,:)=rand(1,10);
end
end
----------------------
However, the case of replacing the 'parfor' with 'for' is 20 times faster. Above code is simplified version of what I'm using. In my real case, 'parfor' should be inside 'for'. Is this a problem?
Could anyone explain why?
Thank you in advance.
  1 个评论
Adam
Adam 2015-2-20
As per Doug's answer since you also only have 2 cores (or are only using 2 cores) you will have to be doing more work to make the parfor setup worthwhile than if you had e.g. 8 cores because the absolute maximum theoretical speedup factor will only be 2 and realistically it is obviously lower than that even when running optimally.

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回答（1 个）

Doug
Doug 2015-2-20
You're not doing enough work in the parfor loop. Since there is an overhead associated with parfor, you have to perform enough operations in the loop to make it worthwhile. Also, it's better if your parfor is not inside a for loop, since otherwise you incur the parfor startup overhead each iteration. You may want to try an example such as http://www.mathworks.com/help/distcomp/examples/simple-benchmarking-of-parfor-using-blackjack.html .

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