清空筛选条件
清空筛选条件

For Loop "Array indices must be positive integers or logical values"

1 次查看（过去 30 天）
IDN
IDN 2022-9-9
回答： Image Analyst 2022-9-9
Good Morning all,
I have the below statement and its not working when i swith signs and i dont understand why. Appreciate the help!
THIS WORKS
for k = 2:nmr
if a(k) > a(k-1) & a(k-1) > a(k-2) & b(k) < b(k-1) & b(k-1) < b(k-2)
result(k) = 1;
elseif result(k)==0
end
end
BUT Once i swith logical signs i get the matlab error
THIS DOESNT WORK
for k = 2:nmr
if a(k) < a(k-1) & a(k-1) < a(k-2) & b(k) > b(k-1) & b(k-1) > b(k-2)
result(k) = 1;
elseif result(k)==0
end
end

请先登录，再回答此问题。

采纳的回答

David Hill
David Hill 2022-9-9
matlab starts indexing at 1, you cannot index into an array at 0
for k = 2:nmr
if a(k) < a(k-1) & a(k-1) < a(k-2) & b(k) > b(k-1) & b(k-1) > b(k-2)
b(k-2) is b(0) when k==2 which cannot happen, matlab will error.
  3 个评论
显示 1更早的评论
David Hill
David Hill 2022-9-9
You could start your loop at 3.
for k = 3:nmr
or do something about the b(k-2)
for k = 2:nmr
if a(k) < a(k-1) & a(k-1) < a(max(1,k-2)) & b(k) > b(k-1) & b(k-1) > b(max(1,k-2))

请先登录，再进行评论。

更多回答（1 个）

Image Analyst
Image Analyst 2022-9-9

类别

在 Help Center 和 File Exchange 中查找有关 Introduction to Installation and Licensing 的更多信息

标签

产品


版本

R2020a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by