Randomise vector numbers to maximum variance

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I have a vector that contains numbers 1, 0 and 10. In partcular, I have 100 times the 1, 400 times the 0 and 20 times the 10.
Is there any function or any way to shuffle the numbers to the maximum variance regarding their repetition? Namely, I want to shuffle them in a way to minimise their sequential repeatibility, so a to achive the low number of times that I get 1,1 or 0,0 or 10,10 in my vector?
Thank you so much in advance!
  4 个评论
Torsten
Torsten 2022-9-9
编辑:Torsten 2022-9-9
Yes, it's obvious that 1 and 10 don't need to repeat and that 0 needs to repeat 279 times. That's optimal and the solution I already posted. Or do you think there is a better one ?
With maximum variance you mean
sum(abs(x(i+1)-x(i)),i=1,...,519)
?
abaza
abaza 2022-9-9
I would like to minimise the repetition.... I cannot avoid repetition of some ZEROS since they are more than 1 and 10, but I would like a more automated way (e.g. when you have more numbers...)

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采纳的回答

Bruno Luong
Bruno Luong 2022-9-9
A = repmat([10 repmat([repmat(0, 1, 2), 1 repmat(0, 1, 2)], 1, 5)], 1, 20);
  10 个评论
Bruno Luong
Bruno Luong 2022-9-9
This is a method for generic case
v=[0 1 10];
n=[400 100 20];
A = shuffle(v, n)
A = 1×520
0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1
function A = shuffle(v, n)
[m,i] = maxk(n,2);
mm = min(m);
if mm > 0
n(i) = n(i)-mm;
A = [repmat(v(i), 1, mm), shuffle(v, n)];
else
[mm,j] = max(m);
A = repmat(v(i(j)), 1, mm);
end
end

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