How to split a string and return only decimal numbers?
12 次查看(过去 30 天)
显示 更早的评论
I would like to extract a vector x containing decimal numbers from this string,
myString = 'YYYY MM DD hh mm .0200 .0325 .0375 .0425 .0475 .0525 .0575 .0625 .0675';
x = [.0200 .0325 .0375 .0425 .0475 .0525 .0575 .0625 .0675]
I have been able to split myString on the white spaces as follows,
splitstring = regexp(myString,'\s+','split');
% 'YYYY' 'MM' 'DD' 'hh' 'mm' '.0200' '.0325' '.0375'
but this doesn't exclude the "words" at the start. Using '\s+[^a-zA-Z]' or '\s+[0-9]' won't return the decimal numbers either.
0 个评论
采纳的回答
Azzi Abdelmalek
2015-2-25
编辑:Azzi Abdelmalek
2015-2-25
myString = 'YYYY MM DD hh mm .0200 .0325 .0375 .0425 .0475 .0525 .0575 .0625 .0675';
out=regexp(myString,'\d?\.?\d+','match')
更多回答(0 个)
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 String Parsing 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!